ax=6⋅cos(60∘)a sub x equals 6 center dot cosine open paren 60 raised to the composed with power close paren
Un vector tiene por componentes A = ( -4, 4 ) . Calcula su módulo y su ángulo director (argumento principal entre 0° y 360°).
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w⃗⋅x⃗=0→2wx−1wy=0→wy=2wxmodified w with right arrow above center dot modified x with right arrow above equals 0 right arrow 2 w sub x minus 1 w sub y equals 0 right arrow w sub y equals 2 w sub x Usamos el dato del módulo:
La combinación de trigonometría y vectores es la base de la física moderna y de la geometría analítica avanzada. Practicar estos ejercicios de forma sistemática te garantizará una excelente calificación en tus evaluaciones de 1º de Bachillerato. ax=6⋅cos(60∘)a sub x equals 6 center dot cosine
Módulos: (|\vecAB| = \sqrt3^2 + 3^2 = \sqrt9 + 9 = \sqrt18 = 3\sqrt2) (|\vecAC| = \sqrt2^2 + 6^2 = \sqrt4 + 36 = \sqrt40 = 2\sqrt10)
✅ Vector suma: módulo ~7.21, ángulo ~103.9°. This link or copies made by others cannot be deleted
R⃗=F1⃗+F2⃗=(6+(-4),0+6.93)=(2,6.93)modified cap R with right arrow above equals modified cap F sub 1 with right arrow above plus modified cap F sub 2 with right arrow above equals open paren 6 plus open paren negative 4 close paren comma 0 plus 6.93 close paren equals open paren 2 comma 6.93 close paren Calculamos el módulo de la resultante: